There are 36 gold cards and 36 silver cards in a deck. The gold cards are numbered 1,3,5,... 71 and the silver cards are numbered 2.4.6,... 72. The cards are throughly shuffled and one card is randomly selected.A. Find the probability of selecting a gold card or a card with a multiple of 12 on it. Show your workB. Find the probability of selecting a silver card or a card with a multiple of 9 on it. Show your work.
Accepted Solution
A:
A) multiples of 12 up to 72 ( 72 total cards)12, 24, 36, 48, 60, 72 = 6 cards.36 are gold. Total gold cards and multiple of 12 = 36 + 6 =42Probability of getting one of them is 42/72, which reduces to 7/12B) 36 silver cardsMultiples of 9: 9, 18, 27, 36, 45, 54,63 = 7 cardsSilver cards are even and there is 3 even cards that are also multiples of 9, so subtract 3 from 7 to get 4. Total silver cards and multiples of 9 = 36 + 4 = 40Probability = 40/72 which reduces to 5/9